12t^2/5+19t^1/5+4=0

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Solution for 12t^2/5+19t^1/5+4=0 equation: 


t in (-oo:+oo)

(12*t^2)/5+(19*t^1)/5+4 = 0

(12*t^2)/5+(19*t)/5+4 = 0

12/5*t^2+19/5*t+4 = 0

DELTA = (19/5)^2-(12/5*4*4)

DELTA = -599/25

DELTA < 0

t belongs to the empty set

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